Calculate the electric field strength required to just support a water drop of mass 10^-7 and have charge 1.6×10^-19c
ANS==> we know that
The farce due to electric field = weight of water drop
E =mg/q
E=10^-7×9.8 /1.6×10^-19
E=6.125×10^12 N/S
Ans:- E=6.125×10^12N\S
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