Calculate the electric field strength required to just support a water drop of mass 10^-7 and have charge 1.6×10^-19c 
  ANS==> we know that 
           The farce due to electric field = weight of water drop 
             E =mg/q
             E=10^-7×9.8 /1.6×10^-19
             E=6.125×10^12 N/S
            Ans:- E=6.125×10^12N\S
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